// Hafizt Maulana Ghojali
// 201181072
// Seksi 2
#include<iostream>
#include<conio.h>
#include<stdio.h>
#include<math.h>
using namespace std;
int main()
{
float XL,XR,E,FXL,FXR,XT,FXT;
XL=3; XR=6; E=0.01;
int n=1;
FXT=fabs(FXT);
printf("\nE = %1.4f\n\n",E);
printf("No. | XL | XR | F(XL) | F(XR) | XT | F(XT) | |F(XT)|<= E\n\n");
why:
FXL=pow(XL,2)-6*(XL)+8;
FXR=pow(XR,2)-6*(XR)+8;
XT=(XL+XR)/2;
FXT=pow(XT,2)-6*(XT)+8;
printf("%d. %1.4f, %1.4f, %1.4f, %1.4f, %1.4f, %1.4f\n",n,XL,XR,FXL,FXR,XT,FXT);
if ( (FXL*FXR) < 0 )
{
if ( fabs(FXT) <= E )
{
printf("\nSolusi (XT)= %1.4f",XT);
printf("\nBatas terakhir loopingnya adalah = %d",n );
}
else
{
if ( (FXL*FXT) > 0 )
{
XL = XT; XR = XR;
n=n+1;
goto why;
}
else
{
XR = XT; XL = XL;
n=n+1;
goto why;
}
}
}
else
{
cout<<"\nTidak Memenuhi Persyaratan";
}
getch();
}
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